Simon 'corecode' Schubert wrote: > On 31.05.2006, at 20:37, [EMAIL PROTECTED] wrote: >>> Style 1: >>> time_t t*; >>> time(t); [...]
>> Also, style 1 is technically "incorrect" since you never allocated the >> memory that t is pointing to before passing it into time(). > maybe the compiler on BSD by chance put NULL into "t" and thus made it a > valid parameter? First, thanks to all who replied! I've been playing with gdb and I'm seeing a significant difference between linux and *BSD. I added a dummy variable to my program, like this: time_t t*, d; and then ran the program in gdb. I printed out t and &d and compared the two values under *BSD and linux. What I see in linux is that the two values are miles apart, but in *BSD they differ by only a few bytes. I *assume* this means that in *BSD, t is pointing to a valid memory location very close to d, whereas in linux t is pointing to some random number. Does this seem a reasonable idea? Thanks again for everyone's help.
