Hi all,
I'm following the "A simple JAX-WS service" section from the overview,
piecing together bits from the "Servlet Transport" doc.
I'm not using Spring.
I've created a simple web service. The class name is "BaseService".
I created a class "WebServicePublisher", which extends
CXFNonSpringServlet. There's one method, the overridden loadBus
method. That method has the following code:
super.loadBus(servletConfig);
Bus bus = this.getBus();
BusFactory.setDefaultBus(bus);
Endpoint.publish("BaseService", new BaseService());
In my web.xml, I added:
<servlet-mapping>
<servlet-name>WebServicePublisher</servlet-name>
<url-pattern>/WSPub</url-pattern>
</servlet-mapping>
When I start tomcat and navigate to /contextname/WSPub, I see a page
titled "CXF - Service list", which shows my the "BaseService" and the
public methods in that class.
Great so far.
However, there's a WSDL link, which I click on that, it goes to:
/contextname/BaseService?wsdl
Which gives me a 404 error. And rightly so .. there's nothing in my
web.xml that configured that URL.
What am I missing?
-d
