Please check
http://cxf.apache.org/docs/debugging-and-logging.html
and see the list of tools you can use to check if the Authorization header is actually available on the wire. I also like TcpTrace :
http://www.pocketsoap.com/tcptrace/
Provided this header is present, you can parse it manually by using JAXRS @HeaderParam. I'm sure there're plenty of Base64 decoding
utils around and CXF has the one too (org.apache.cxf.common.util.Base64Utility).
Alternatively youy can have a @Context MessageContext parameter passed in too
and then do
mc.get(AuthorizationPolicy.class.getName());
Sergey
----- Original Message -----
From: "SaravananRamamoorthy" <[email protected]>
To: <[email protected]>
Sent: Wednesday, February 03, 2010 4:29 PM
Subject: Re: Http basic authentication in JAX RS
Hi Sergey,
Thanks for your suggestions.
I am new to apache cxf.
Is there any direct interface or context availabe to receive the
authentication details just like @QueryParam.(for receiving query string).
It is enough to print the username and the password in the console.
Please provide the solution.
Regards
Saravanan R
Sergey Beryozkin-2 wrote:
Actually, just looked at the source of MessageContextImpl, it should be
mc.get(AuthorizationPolicy.class.getName()) when retrieving
it from MessageContext given that uses toString() on the object keys.
Also make sure you're actually seeing an Authorization header on the wire
cheers, Sergey
Hi Sergey,
I tried with your suggestions like
public Response getCredentials(@Context MessageContext mc)
{
AuthorizationPolicy policy =
(AuthorizationPolicy)mc.get(AuthorizationPolicy.class);
System.out.println(policy.getUserName());
.......
.......
When I tried to give the Authentication from SOAP UI, I got null.
Please correct me where I did the mistake.
Regards
Saravanan R
Sergey Beryozkin-2 wrote:
Hi
The only way at the moment to get AuthorizationPolicy object in the app
code is to do something like this :
@Context MessageContext mc;
....
AuthorizationPolicy policy =
(AuthorizationPolicy)mc.get(AuthorizationPolicy.class);
cheers, Sergey
Hi All,
I am creating REST application using JAX RS.
I am using SOAPUI to test the application.
My Rest needs to receive the Http Basic Authentication from the
SOAPUI.
I just want to receive the authentication details like
username,password and
domain in JAX RS method.
Can anyone give the idea how to get the authentication details in the
parameter of the method.
I ended up not needing this, but I experimented with creating an
"AuthorizationRequestHandler" class (implements RequestHandler) and
putting that in my "jaxrs:providers" list. That requires a
"handleRequest(Message message, ClassResourceInfo classResourceInfo)"
method, where I can call "AuthorizationPolicy policy =
message.get(AuthorizationPolicy.class);". The AuthorizationPolicy
contains the username and password.
What is not clear to me, however, is where this object is available
somehow at the controller level.
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