Hi Sergey, I added the params in web.xml but JAXRS still does not log inbound and outbound messages. FYI, I'm still using 2.2.5, and I checked the set Interceptor are implemented in CXFNonSpringJaxRsServlet.
regards, Loh Kok Jeng On 4 June 2010 15:46, Loh Kok Jeng <[email protected]> wrote: > Hi Sergey, > > Many thanks. > > Do u mean add the following to web.xml? > > <init-param> > <param-name>jaxrs.inInterceptors</param-name> > > <param-value>org.apache.cxf.interceptor.LoggingInInterceptor</param-value> > </init-param> > > <init-param> > <param-name>jaxrs.outInterceptors</param-name> > > <param-value>org.apache.cxf.interceptor.LoggingOutInterceptor</param-value> > </init-param> > > regards, > Loh Kok Jeng > > > > On 4 June 2010 04:39, Sergey Beryozkin <[email protected]> wrote: >> Hi >> >> You'll need to register CXF LoggingInInterceptor and LoggingOutInterceptor >> using >> >> jaxrs.inInterceptors and jaxrs.outInterceptors servlets parameters >> >> cheers, Sergey >> >> >> On Thu, Jun 3, 2010 at 11:06 AM, Loh Kok Jeng <[email protected]> wrote: >> >>> Hi, >>> >>> I'm implementing a REST server using CXFNonSpringJaxrsServlet. Below >>> is a snippet of my REST server. >>> >>> Question: how can I log inbound and outbound message for this REST server? >>> >>> public class RestApp extends Application { >>> >>> �...@override >>> public Set<Class<?>> getClasses() { >>> // TODO Auto-generated method stub >>> Set<Class<?>> set = new HashSet<Class<?>>(); >>> >>> set.add(SomeServiceJaxRS.class); >>> } >>> } >>> >>> >>> regards, >>> Loh Kok Jeng >>> >> >
