Oliver, On Tuesday, June 21, 2011 7:51:43 PM Oliver Wulff wrote: > I was thinking that it must be possible to figure this out at startup time. > I remember that I read that there was some refactoring regarding the > different http transports which would simplify the way to get this > information.
No, Willem is right. There isn't anything in the Servlet context or config that would allow you to get that information. It's partially because a single servlet can be bound to multiple locations and different ports and such. Thus, it's only during the invoke that you can determine how the client contacted the servlet. Dan > I think it's error prone to configure it in the spring config if everything > is already configured in tomcat server.xml and the web app name (servlet > context name). > > Thanks > Oli > > ________________________________________ > Von: Willem Jiang [[email protected]] > Gesendet: Montag, 20. Juni 2011 12:03 > An: [email protected] > Betreff: Re: Fully qualified endpoint address at startup time > > It's hard to know what the exactly the services address is when you > start the the endpoint in the servlet or osgi container. > The address will be changed if your war or servlet configure is changed. > > If you already know the physical address, you may consider to use > publishedEndpointUrl property to set the address which will be used in > the WSDL that is generate dynamically from CXF. > > <jaxws:endpoint id="myEndpoint" address="MyServicePort" > serviceClass="org.apache.hello_world_soap_http.GreeterImpl" > > <jaxws:properties> > <!-- Set the publishedEndpointUrl which could override the service > address from generated WSDL as you want --> > <entry key="publishedEndpointUrl" > value="http://www.simple.com/services/test"; /> > </jaxws:properties> > </jaxws:cxfEndpoint> > > On 6/18/11 2:42 PM, Oliver Wulff wrote: > > Hi there > > > > Does there exist a way to figure out the fully qualified endpoint > > address for an http based endpoint at startup time independent of the > > underlying container (servlet, osgi, jetty)? > > > > The following way works for an incoming request but I'm looking for a > > way during startup: > > > > HttpServletRequest req = (HttpServletRequest)msg.get("HTTP.REQUEST") > > if (req != null) { > > ... = req.getRequestUrl(); > > } > > > > > > Thanks > > Oli > > -- > Willem > ---------------------------------- > FuseSource > Web: http://www.fusesource.com > Blog: http://willemjiang.blogspot.com (English) > http://jnn.javaeye.com (Chinese) > Twitter: willemjiang > Weibo: willemjiang -- Daniel Kulp [email protected] http://dankulp.com/blog Talend - http://www.talend.com
