Note #2 here shows how to determine the SOAP address (at least for
standalone Tomcat, should be same in your case):
http://www.jroller.com/gmazza/entry/web_service_tutorial#notes
HTH,
Glen
On 09/26/2012 03:20 AM, georgenis wrote:
Hi community,
i have got a simple question. I got an embedded Tomcat in my application.
Now i will expose an webservice via spring.
<jaxws:endpoint id="userService"
implementor="com.integration.ws.impl.UserService" address="/UserService"/>
<bean id="tomcat" class="com.server.EmbeddedTomcat"
init-method="start">
<property name="contextPath" value="/openflow" />
<property name="port" value="8081" />
<property name="servlet">
<bean
class="org.apache.cxf.transport.servlet.CXFServlet" />
</property>
</bean>
But I cant find the URL where my service is published?! I tried a lot of
different urls, but i cant find my service?!
My CXFServlet says -> No service...
Can anyone help me please?
Best regards
gk
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Glen Mazza
Talend Community Coders - coders.talend.com
blog: www.jroller.com/gmazza
