On 25/10/12 22:00, Sergey Beryozkin wrote:
Hi, sorry I did not have time today to experiment.
What happens if you start from accessing "/greeter" first, does
"/greeter2" becomes unaccessible ? Or "/greeter" is not visible at all ?
I'll have more into it next week as I'm tomorrow and Monday
Well, my typing is not something I seem to be able to control at the
moment. I'll look into it next week :-)
Sergey
Sergey
On 24/10/12 22:18, Marco Speranza wrote:
Hi all,
I'm trying to register two REST service into Jetty using CXF multi
bundle distro, but it seems that only the last service is correctly
register and deploy.
I try to explain my configuration:
my OSGI Activator is:
public void start(BundleContext bc) throws Exception {
Dictionary props = getProperties("/greeter");
registration = bc.registerService(CategoryServiceRest.class.getName(),
new CategoryServiceRestImpl(), props);
props = getProperties("/greeter2");
registration = bc.registerService(SessionServiceRest.class.getName(),
new SessionServiceRestImpl(), props);
}
private Dictionary getProperties(String address) {
Dictionary props = new Hashtable();
props.put("service.exported.interfaces", "*");
props.put("service.exported.configs", "org.apache.cxf.rs");
props.put("service.exported.intents", "HTTP");
props.put("org.apache.cxf.rs.httpservice.context", address);
props.put("org.apache.cxf.rs.provider",
"org.codehaus.jackson.jaxrs.JacksonJaxbJsonProvider");
return props;
}
when I invoke the Session REST WS all work fine but when I try to
invoke greeter/category web service I experienced this error:
2012-10-24 23:05:31,116 | WARN | qtp1188024874-85 | JAXRSInInterceptor
| 92 - org.apache.cxf.bundle-minimal - 2.5.2 | No root resource
matching request path /greeter/category/getRoots has been found,
Relative Path: /greeter/category/getRoots. Please enable FINE/TRACE
log level for more details.
2012-10-24 23:05:31,123 | WARN | qtp1188024874-85 |
WebApplicationExceptionMapper | 92 - org.apache.cxf.bundle-minimal -
2.5.2 | WebApplicationException has been caught : no cause is available
Can anyone help me?
thanks in advance
--
Marco Speranza<[email protected]>
Google Code: http://code.google.com/u/marco.speranza79/
--
Sergey Beryozkin
Talend Community Coders
http://coders.talend.com/
Blog: http://sberyozkin.blogspot.com
