Hi, You can add @WebService annotation for the service Impl or SEI class where you can specify the wsdlLocation －－－－－－－－－－－－－ Freeman(Yue) Fang
Red Hat, Inc. FuseSource is now part of Red Hat Web: http://fusesource.com | http://www.redhat.com/ Twitter: freemanfang Blog: http://freemanfang.blogspot.com http://blog.sina.com.cn/u/1473905042 weibo: @Freeman小屋 On 2013-4-10, at 下午2:11, Ted Roeloffzen wrote: > Thank you Glen, the problem is that we don't use a cxf-servlet.xml, we > create the endpoints in code. > > javax.xml.ws.Endpoint endpoint = > javax.xml.ws.Endpoint.create(webserviceImpl); > endpoint.publish(address); > > Can i set the wsdllocation when creating an endpoint in code? > > > > 2013/4/9 Glen Mazza <[email protected]> > >> The wsdlLocation field in the cxf-servlet.xml file should do it for you: >> http://www.jroller.com/gmazza/**entry/web_service_tutorial#**WFstep6<http://www.jroller.com/gmazza/entry/web_service_tutorial#WFstep6> >> >> Note the endpoint URL in the WSDL will still get overwritten based on >> deployment configuration decisions you've made, as discussed in note #2 >> here: >> http://www.jroller.com/gmazza/**entry/web_service_tutorial#**notes<http://www.jroller.com/gmazza/entry/web_service_tutorial#notes> >> >> Glen >> >> >> On 04/09/2013 10:00 AM, Ted Roeloffzen wrote: >> >>> Hello all, >>> >>> I'm having some difficulty with CXF. >>> I got a WSDL from an external party and used this to create a >>> webservice-server. >>> For this I used de codegen-plugin for maven. >>> >>> When I check the definition of the server, by going to the url and adding >>> ?wsdl, then I receive a WSDL that seems to be generated by CXF and has an >>> import to the WSDL that i used to generate the code. >>> The problem is that the external party can't connect with our server >>> because of the differences between the WSDL's. >>> >>> Is it possible to tell CXF not to generate a wsdl, but return the WSDL >>> that >>> is in the import-statement? >>> >>> best regards, >>> >>> Ted >>> >>> >>
