This appears to be the answer:
// Check if CXF can make a decision
int cxfResult= super.compare(oper1, oper2);
if (cxfResult != 0)
return cxfResult;
Int result = 0;
String s = … message body.
String target= null;
if (s.startsWith(“banana”))
target= "updateFruit";
else if (s.startsWith(“dog”))
target= "updateAnimal";
if (target!=null) {
if (m1.equals(m2) && m1.equals(target))
result = 0;
else if (m1.equals(target))
result= -1;
else if (m2.equals(target))
result= 1;
else
result= m1.compareTo(m2);
}
return result;
--
John Baker
On Mon, Jul 29, 2013, at 01:51 PM, John Baker wrote:
>
> > The relevant RC method needs to help with ordering the method
> > candidates, so return either -1 or 1 to help the runtime choose the
> > right candidate
>
> But what is "equal"? Is it the two resource infos pointing to
> updateFruit when i know the target is that method? So return 0 in that
> case?
>
> And what's the algorithm when two different resource infos are passed,
> that may or may not be updateFruit?
>
> (I think there may be an easier way to write this interface - simply
> list through the methods calling a method on an interface that returns
> true or false - but that's a discussion for another day.)
