Basic JPA querying works fine:
Query query = em.createQuery("SELECT p FROM Patient p where
p.lastname=:lastname");
query.setParameter("lastname", "Silver");
List<Patient> patients = query.getResultList();
I checked OPENJPA-2056. We have standard_conforming_strings property in
Postgresql set to OFF.
I also included this in my persistence.xml, as suggested in the article:
<property name="openjpa.jdbc.DBDictionary"
value="postgres(SearchStringEscape=\)"/>
But it had no affect.
You mentioned calling CriteriaBuilder.equal to bypass the LIKE issue, but if
CriteriaBuilder is being used internally by CXF, how could I bypass this
and use it directly in my code?
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