Hi
On 16/04/14 13:54, gangaaloori wrote:
Hi,
I'm using CXF 3.0.0-milestone2 version for exposing a REST API. I would like
to validate the incoming request which I'm able to do using the
JAXRSBeanValidationInInterceptor. If I'd like to return a good validation
error message to the caller, How do I get/access the parameter name which
caused the validation exception?
After a quick search I found that out there is a way, by implementing the
"javax.validation.ParameterNameProvider" interface. Luckily CXF source code
has got an example java class - JAXRSParameterNameProvider.java.
Now my question is - How do I register/configure this class within CXF
context?
Just FYI - I'm using spring to configure the jaxrs server
This interceptor (like all other validation interceptors) can be
injected with the custom
org.apache.cxf.validation.BeanValidationProvider, it is created by
default, but it can be customized, one of its constructors accepts
ParameterNameProvider, the other one -
org.apache.cxf.validation.ValidationConfiguration which can be used to
completely customize the process.
I'll need to update the documentation
Thanks, Sergey
Thanks,
Ganga Aloori
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Sergey Beryozkin
Talend Community Coders
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