Le 2 sept. 2013 à 18:15, Murad Mamedov <[email protected]> a écrit :

> Hello, I'm newbie here, but using OSGi for long time.
> 
> From my understanding of your problem:
> - you expect some bundles to have build.xml
> - you are a build system that does somethings with those bundles.
> If above is true, I would start BundleListener and listen bundle events. Of
> course, on startup of build system you will need to get the initial list of
> bundles your self.
> Once BundleListener gets event on installed bundle, I would check if it is
> my bundle (has build.xml for example) and keep it in private map (ex:
> taskName -> Bundle).
> This will be faster and more dynamic, better than traversing over bundles
> every time.

The thing is that I don't expect a "build" bundle to only have a build.xml at a 
precise location. I could be anywhere, named in any way. For instance there can 
be a bundle in which there would be a common-build-java.xml and a 
common-build-resources.xml, in anther bundle a common-build-webapp.xml which is 
importing the former ones, and my main build.xml is just importing the later 
one.

I would really like the build files to behave like Java classes in this OSGi 
environment.

> But I'm still not sure if you can access actual ClassLoader of that bundle
> even if you have it and for example instantiate some class from there.
> You have to depend (import somethings from it) on that bundle, but as far
> as I understand you expect unknown user ant tasks to be around in unknown
> user bundles.
> Is it possible to get actual class loader of some bundle and do something
> with it?

Well, I don't need a classloader per se. To make a build file load an Ant task, 
I need something to load a class, so Bundle#loadClass() is fine. And to make a 
build file import another one, I need something to load a resource, so 
Bundle#findEntries() is fine too.

> Using services could be a better option for this problem in my opinion.

Could you elaborate on that ? I know a little bit about services but not enough 
to understand what kind of solution you are thinking of.

cheers,
Nicolas

> 
> Regards,
> Murad
> 
> 
> 
> On Mon, Sep 2, 2013 at 5:59 PM, Nicolas Lalevée
> <[email protected]>wrote:
> 
>> 
>> Le 2 sept. 2013 à 10:34, Christian Schneider <[email protected]> a
>> écrit :
>> 
>>> I think it would be a bad idea to rely on an URI scheme. After all it is
>> not specified in the OSGi standard.
>>> Can't you simply forward the bundle or classloader together with the URL?
>> 
>> The URL is pointing to a build file which I want to "run" within its
>> bundle just like a java class would do. When running it will probably need
>> to load resources, and I want this loading to follow the OSGi visibility
>> rules. So I would need the classloader which "owns" that resource, and I
>> don't have it, the OSGi framework has.
>> 
>> Nicolas
>> 
>>> 
>>> Christian
>>> 
>>> On 02.09.2013 10:13, Nicolas Lalevée wrote:
>>>> Le 1 sept. 2013 à 22:28, Richard S. Hall <[email protected]> a
>> écrit :
>>>> 
>>>>> I'm pretty sure this isn't possible for resources, like it is for
>> classes.
>>>>> 
>>>>> The OSGi spec doesn't mandate the format of bundle resource URLs,
>> which is what you would need if you wanted to determine from which bundle a
>> looked up resource comes.
>>>>> 
>>>>> Not sure about other frameworks, but this is fairly easy to determine
>> from a resource URL in the Felix framework, since this host is the bundle
>> id + revision id.
>>>> I can do an if(felix) in my code to optimize. In the long term can I
>> rely on this URL scheme ?
>>>> 
>>>> Nicolas
>>>> 
>>>> 
>>>>> -> richard
>>>>> 
>>>>> On 9/1/13 11:31 , Nicolas Lalevée wrote:
>>>>>> Hi,
>>>>>> 
>>>>>> Maybe my issue has already been addressed several time, so here is
>> the actual question: how can I get the bundle/classloader which *owns* the
>> URL which I looked up through classloader.getResource(file) ?
>>>>>> 
>>>>>> If it's not clear, here is my context.
>>>>>> 
>>>>>> I am experimenting a build system where some Ant build files and Ant
>> task would be managed like as OSGi bundles. So I can do a modularisation of
>> build files and jars of Ant Tasks.
>>>>>> 
>>>>>> At some point a build file (within a bundle) will have to load some
>> other Ant script (through the bundle wiring). For that I simply get the
>> classloader of the current classloader and do a
>> classloader.getResource("/path/other/build.xml"). So far so good.
>>>>>> But when running that other build file, I would need its classloader
>> to do some other import of build.xml file. But I only have the resolved
>> URL, not the bundle which is containing the resolved script. Which java
>> code, it's simple, from the resolved class I can get its classloader. But I
>> cannot do that for a script which as been resolved as an URL.
>>>>>> 
>>>>>> Here is what I have manage to do so far but I find it not pretty:
>>>>>> 
>>>>>>    URL buildUrl = currentClassLoader.getResource(buildFile);
>>>>>>    ClassLoader buildClassLoader = null;
>>>>>>    for (Bundle bundle : allBundles) {
>>>>>>        BundleWiring wiring = bundle.adapt(BundleWiring.class);
>>>>>>        int i = buildFile.lastIndexOf('/');
>>>>>>        String path = buildFile.substring(0, i);
>>>>>>        String name = buildFile.substring(i + 1);
>>>>>>        List<URL> entries = wiring.findEntries(path, name, 0);
>>>>>>        if (!entries.isEmpty() && containsUrls(entries, buildUrl)) {
>>>>>>            buildClassLoader = wiring.getClassLoader();
>>>>>>            break;
>>>>>>        }
>>>>>>    }
>>>>>>    if (buildClassLoader == null) {
>>>>>>        throw new RuntimeException("WTF! Unable to find the
>> classloader of the build file " + buildFile);
>>>>>>    }
>>>>>> 
>>>>>> It is working but it doesn't sound nice. Is there an API I didn't
>> found which allows to look for a resource and its bundle or classloader ? I
>> would prefer an OSGi API, but if it's a Felix one I don't mind.
>>>>>> 
>>>>>> Nicolas
>>>>>> 
>>>>>> 
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>>>>>> 
>>>>> 
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>>> 
>>> 
>>> --
>>> Christian Schneider
>>> http://www.liquid-reality.de
>>> 
>>> Open Source Architect
>>> http://www.talend.com
>>> 
>>> 
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>>> 
>> 
>> 
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