Using uint removes the padded 'f' . Is that correct or the value returned from uint is correct?
-- Saju Thankathurai Sent from my Samsung Galaxy Ace. On 14 Oct 2014 22:01, "Kessler CTR Mark J" <[email protected]> wrote: > Well hex numbers work in the similar way a UINT works by treating it as > all positive. Meaning... > > > uint(-214748364). toString(16).toUpperCase(); > > > BTW this removes the padded "F"s. > > > -Mark > > -----Original Message----- > From: Saju Thankathurai [mailto:[email protected]] > Sent: Tuesday, October 14, 2014 11:52 AM > To: [email protected] > Subject: Re: Decimal to Hex conversion. > > But Number("-214748364").toString(16).toUpperCase(); returned me only > -CCCCCCC. > > How can we get the value FFFF FFFF F333 3334? > > > -- > Regards > > Saju Thankathurai, > > > On Tue, Oct 14, 2014 at 9:08 PM, Kessler CTR Mark J < > [email protected]> wrote: > > > Oh didn't notice the negative sign. > > Yes that changes it to the other way. > > > > -214,748,364 = FFFF FFFF F333 3334 > > > > -Mark > > >
