I’m not sure your example was valid. If you instead had:
Var xml:XML = <Project Name="Project1">
<Subproject Name=“Subproject1" ID="2293" attr1="1.00" attr2="2.00"/>
<Subproject Name=“Subproject2" ID="2294" attr1="1.00" attr2=“3.00"/>
<Subproject Name=“Subproject3" ID="2295" attr1=“2.00" attr2="2.00"/>
</Project>
Then I think you would use
xml.SubProject.(@attr1==“1.00” && @attr2==“2.00”).@ID
On 11/19/14, 11:19 AM, "mark goldin" <[email protected]> wrote:
>Let's say I have the following code:
><Project Name="Project1" ID="2293" attr1="1.00" attr2="2.00">
> <Subproject Name="Subproject1"/>
> <Subproject Name="Subproject2"/>
> <Subproject Name="Subproject3"/>
></Project>
>
>I'd lit to find ID="2293" based on a fact that the element has both attr1
>and attr2.
>
>Thanks for help.
