COUNT a total for each diagnosis present, not just where diagnosis=ptsd. SELECT "Diagnosis", COUNT (*) AS "Count Patients" FROM "Patients" GROUP BY "Diagnosis" HAVING COUNT(*)> 10 ORDER BY "Count Patients" DESC
Selects the count for each type of diagnosis. The last 2 clauses are optional. HAVING does the same with the outgoing results like the WHERE clause does with the incoming table data. ORDER BY can order by arbitrary columns, even when they are not in the SELECT. Each SELECTed field that is not an aggregation (sum,count,min,max,,...) needs to be repeated in the group clause. Each unique combination of the grouped fields gets the function results. SELECT A,B,C, SUM(X),COUNT(Y),MAX(Z) FROM BLAH GROUP BY A,B,C gets the sum(x), count(y), max(z) for each combination of A,B,C -- View this message in context: http://nabble.documentfoundation.org/BASE-Query-Report-tp3298830p3300701.html Sent from the Users mailing list archive at Nabble.com. -- For unsubscribe instructions e-mail to: [email protected] Problems? http://www.libreoffice.org/get-help/mailing-lists/how-to-unsubscribe/ Posting guidelines + more: http://wiki.documentfoundation.org/Netiquette List archive: http://listarchives.libreoffice.org/global/users/ All messages sent to this list will be publicly archived and cannot be deleted
