Hi :)
Someone else asked a very similar question about a month ago and i think 
someone created a neat calculation or spreadsheet to help figure it out.  Now 
the trick is trying to find it in the archives!
Good luck and regards from
Tom :)  





>________________________________
> From: zr1hpc <[email protected]>
>To: [email protected] 
>Sent: Thursday, 14 February 2013, 6:07
>Subject: [libreoffice-users] Calc scale formula conundrum/ logic confusion
> 
>Using Calc 3.4.5 on openSuse 11.2
>
>I am trying to work out the currency value of the amount of electricity
>units I have left at the end of the month (G2).
>
>This same formula will be used for the other 11 months of the year with only
>the G2 reference changing to G3, G4...etc.
>For those who wish to stretch their grey matter as mine just ain't
>stretching any more.
>
>The pricing scale the energy supplier has given me is:
>
>Unit Range        Value per unit
>0-150            1.1320
>150.01 -> 600    1.1811
>600.01 ->        1.4018
>
>Therefore the first 150 units are priced at 1.132 ea. any units still
>available need to be calculated at the next rate of 1.1811, but only up to
>449.90 units at the second rate. Anything more than that must be at the
>highest rate of 1.4018.
>
>Assuming my unit balance of G2 = 433 I can work out the currency value of G2
>by following the following logic, and using the scale above:
>
>433 > 150 therefore the initial 150 units need to be priced at 1.1320 i.e.
>150* 1.132= ZAR169.80. To this the balance of the units over 150 need to be
>multiplied by the next rate of 1.1811 i.e. 433-150= 283. Since 283 is below
>the max of 449.9 units allowed for this scale, therefore 283*1.1811=
>ZAR334.25. The third scale is not needed as all the units have been
>accounted for, however it must be available should G2 exceed 600 units e.g.
>taking 601 units; the first 150 would be costed at 1.132, the next 449.9
>costed at 1.1811 and the balance of 1.1 units costed at 1.4018 per unit.
>
>Therefore total value of 433 units is:
>  150*1.1320 = 169.80
>+ 283*1.1811 = 334.25
>_____________________
>Value        ZAR504.05
>
>Values used in formulae below are:
>G2 = 433 available units
>$F$18 = 1.132 cost per unit
>$G$18 = 0 -> 150 units
>$H$18 = 169.80 = value of F*G
>$I$18 = 1.1811 cost per unit
>$J$18 = 150.1 -> 600 units
>$K$18 = 531.38 = value of I*449.90 = 600-150.1
>$L$18 = 1.4018 cost per unit
>$M$18 = 600.01
>$N$18 = 841.09 = M*L however this value is dependent on how many units
>        over 600 column G2:g13 is.
>
>SUM(IF(G2>=$G$18,$H$18,(G2-$G$18)*$F$18),IF($G$18>(G2-$G$18)<=$J$18,$K$18,(G2-$G$18)*$I$18),IF((G2-$G$18-$J$18)>=$M$18,$N$18,(G2-$G$18-$J$18)*$L$18))
>
>Even taking out the SUM(), and replacing 'commaIF' with '+IF's gives the
>incorrect answer i.e. 467.22.
>
>There must be a problem with my logic in the above formula as the answer is
>so close, but for the life of me I cannot see it.
>
>Asking for some 'logic'al help to work out the correct value in H2:H13
>
>File attached via Nabble:  Electricity.ods
><http://nabble.documentfoundation.org/file/n4037350/Electricity.ods>  
>
>Appreciated
>Hylton
>-- 
>========================================================================
>Hylton is a Lions Club member of Lions Club of Fish Hoek (District 410A)
>http://e-clubhouse.org/sites/fishhoek/index.php being part of the worlds
>largest non profit NGO
>========================================================================
>
>
>
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