At 15:55 13/08/2014 +1000, Keith Bates wrote:
While I agree with most of your post, a slight typo or something
crept in here, where you confuse 10^53 with 2^53
2^53 is one followed by fifty-three zeroes, of course - so is just
too long to be stored accurately.
I wasn't clear - but not in the way you thought! I meant that 2^53 is
represented *in binary* (as it will be in the computer) as one
followed by fifty-three zeroes, of course. So it's the value that is
just too large to be stored accurately in double precision. (As so
often happens, I spotted that omission just after I had sent the message!)
Brian Barker
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