Hi Rayson,
Thanks for your reply. I have tried using -v to pass variables to
awk, but it is not working correctly. I think it's because my script
requires all variables to be escaped and I don't know how to pass the
escape symbol correctly.
line2=$(awk -v "task_id=$SGE_TASK_ID" 'NR==task_id' "/myPath/
fileList.txt" )
echo \$line2
has a blank output, but so does
line2=$(awk -v "task_id=\$SGE_TASK_ID" 'NR==task_id' "/myPath/
fileList.txt" )
echo \$line2
Can you give me any insight into passing the escape sign or why I am
needing to escape all the variables in my script?
Thanks,
Sara
On Apr 16, 2012, at 9:13 PM, Rayson Ho wrote:
line2=$(awk -v "task_id=$SGE_TASK_ID" 'NR==task_id' "/tmp/
fileList.txt" )
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