Re: XML node access by variable

[Carl Marcum]

On 03/11/2016 03:08 AM, bartoleo wrote:

One way is using 'index notation':

report.R.each {item ->
  println item[myTag]
}

or GString
report.R.each {item ->
  println item."$myTag"
}

report.R."$myTag".each {item ->
  println item
}

Leo

2016-03-11 5:46 GMT+01:00 Carl Marcum [via Groovy] <[hidden email] </user/SendEmail.jtp?type=node&node=5731833&i=0>>:

    I'm using XML Slurper to parse an XML file with this type of format:

    <R>
       <C0>...</C0>
       <C1>...</C1>
       <C2>...</C2>
    </R>
      <R>
       <C0>...</C0>
       <C1>...</C1>
       <C2>...</C2>
    </R>
    ...

    The XML file node names are constantly changing so I would like to
    use a
    variable for the node designations.

    defreport =newXmlSlurper().parse(myXmlFile)

    instead of access the C1 node like:
    report.R.each() {item ->
    item.C1
    }

    I'm using:
    def myTag = "C1"
    report.R.each {item ->
    item.getProperty(myTag)
    }

    Is there a shorter way to access the node by variable without
    getProperty(tagVar)?

    Thanks,
    Carl Marcum
    Apache OpenOffice committer and PMC



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--
Leo Bartoloni

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That's great!

Thanks Leo !!

Carl