Hi Guy
Just assign the variable
def comapreVersions = { a,b ->
return getVersion(a).toInteger() <=> getVersion(b).toInteger()
}
and then use it in your sort:
list.sort(compareVersions)
Best regards,
Søren Berg Glasius
GR8Conf Europe organizing team
GR8Conf ApS
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--- GR8Conf - Dedicated to the Groovy Ecosystem
From: Guy Matz <guym...@gmail.com>
Reply: users@groovy.apache.org <users@groovy.apache.org>
Date: May 16, 2016 at 17:28:34
To: users@groovy.apache.org <users@groovy.apache.org>
Subject: re-using a comparison closure
Hi!
I have to sort a list of strings based on a number within the string . . . I
am able to sort using something like:
list.sort( { a,b -> getVersion(a) <=> getVersion(b)})
I need to use this in a bunch of places in my code and was hoping to replace it
with a method, like:
list.sort( compareVersions)
with compareVersions:
def compareVersions(a, b) {
return getVersion(a).toInteger() <=> getVersion(b).toInteger()
}
putting the method (compoareVersions) into the sort as a param doesn't work.
Anyone know what I'm missing?
Thanks!!
Guy
