Looks like a bug to me, I can reproduce in 2.4.7. The good news is that if you
have a method taking the Function, like:
static void calc(Function<Integer, Integer> fct) { println fct.apply(10) }
Then you can call it with calc { -it }
You can use the trick to define an identity function to trick the static
compiler:
static Function<Integer, Integer> f(Function<Integer, Integer> fct) { fct }
Function<Integer, Integer> fct = f { -it }
However, I could not get the following signature to work:
static <A, R> Function<A, R> f(Function<A, R> fct) { fct }
If you don't need full type checking, the following does work:
Function fct = { Integer n ->
return 1
}
Jason
-----Original Message-----
From: cazacugmihai [mailto:[email protected]]
Sent: Friday, September 02, 2016 9:06 AM
To: [email protected]
Subject: Static type checking
Hi,
I have a problem running this code:
import groovy.transform.CompileStatic
import java.util.function.Function
@CompileStatic
class Test {
static void main(String[] args) {
// this code fails
Function<Integer, Integer> fct = { Integer n ->
-n
}
// this one works but it is too verbose
// Function<Integer, Integer> fct = ({ Integer n ->
// -n
// } as Function<Integer, Integer>)
println fct.apply(10)
}
}
The error:
Test.groovy: 9: [Static type checking] - Incompatible generic argument types.
Cannot assign java.util.function.Function <java.lang.Integer,
groovy.lang.Closure> to: java.util.function.Function <Integer, Integer> @ line
9, column 36.
Function<Integer, Integer> fct = { Integer n ->
^
1 error
[Finished in 0.5s]
Is there a bug in groovy related to @CompileStatic or maybe I am missing
something else? I just don't want to write redundant code.
Thanks,
Mihai
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