Thank you, David. I assume that there's no way to achieve the behavior I
described. The following is a very naive work around I just wrote:
def multiple_assignment(int assignments, List values) {
assert assignments >= 0
assignments = Math.min(values.size() - 1, assignments - 1)
values.take(assignments) << values.takeRight(values.size() -
assignments)
}
def (a, b, c) = [1, 2, 3, 4]
assert a == 1 && b == 2 && c == 3
(a, b, c) = multiple_assignment(1, [1, 2, 3, 4])
assert a == [1, 2, 3, 4] && b == null && c == null
(a, b, c) = multiple_assignment(2, [1, 2, 3, 4])
assert a == 1 && b == [2, 3, 4] && c == null
(a, b, c) = multiple_assignment(3, [1, 2, 3, 4])
assert a == 1 && b == 2 && c == [3, 4]
(a, b, c) = multiple_assignment(4, [1, 2, 3, 4])
assert a == 1 && b == 2 && c == 3
(a, b, c) = multiple_assignment(5, [1, 2, 3, 4])
assert a == 1 && b == 2 && c == 3
