Apache 2.0.51 Solaris 9
Im trying to get 1 file, show.cgi, to execute outside of /cgi-bin/
show.cgi (PERL) resides under /foo/bar For now show.cgi is just a
"Hi" program.
#!/usr/bin/perl -T
use strict;
use warnings;
printf("Content-Type: text/html\n\n");
printf("hi");
owner: nobody perms: 555 Executes fine from the commandline.
For most part I know what needs to be added to make this work, but Im
getting the source code on the screen, instead of the output.
Nothing in the error log; access log returns a 200.
I looked at http://httpd.apache.org/docs/2.0/howto/cgi.html to see if
I was missing anything. Apparently not.
<Directory "/usr/local/apache/htdocs/foo/bar">
AllowOverride Options
Options +ExecCGI
<IfModule mod_mine.c>
# <Files "show.cgi">
AddHandler cgi-script .cgi
# </Files>
</IfModule>
</Directory>
Ive looked at the other directives for /foo and for /, but I cannot
see anything that would cause the source code to print out. I dont
use .cgi extensions anywhere else on the web server.
What could I be forgetting?
Thanks
Birl
Please do not CC me responses to my own posts.
I'll read the responses on the list.
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