----- Original Message -----
From: "Juan Luis Baptiste" <[EMAIL PROTECTED]>
Date: Tue, 09 Jul 2002 07:07:52 +0800
To: [EMAIL PROTECTED]
Subject: Fw: Ejemplo numeros de secuencia


> Hi Grigory,
> 
> First of all thanks for your answer, it helped me very much to understand the seq 
>number renumbering problem.
> 
> But I have a cuestion about your example, I think it only works when all packets 
>arrive ordered, not when one or more get delayed and the packets start arriving in 
>desorder. Please see this modified version of your example, please look at nueral 5.
> 
> 
> 
> 1) (OUT) IPv4            <-        IPv6     Dout = 0, Din = 0
> 
> L4 = 20                                   <-        L6 = 50              D'out = 
>-30, D'in = 0
> 
> SN'out = SNout + Dout = 100            <-        SNout = 100
> 
> AN'out = ANout - Din = 500  <-        ANout = 500
> 
> Result: Dout += D'out = -30, Din += D'in = 0
> 
>  
> 
> 2) (IN) IPv4    -> IPv6            Dout = -30, Din = 0
> 
> L4 = 40                   -> L6 = 60          D'out = 0, D'in = 20
> 
> SNin = 500      -> SN'in = SNin + Din = 500
> 
> ANin = 120     -> AN'in = ANin - Dout = 150
> 
> Result: Dout += D'out = -30, Din += D'in = 20
> 
>  
> 
> 3) (OUT) IPv4            <-        IPv6     Dout = -30, Din = 20
> 
> L4 = 40                   <-            L6 = 40           D'out = 0, D'in = 0
> 
> SN'out = SNout + Dout = 120            <-        SNout = 150
> 
> AN'out = ANout - Din = 540  <-        ANout = 560
> 
> Result: Dout += D'out = -30, Din += D'in = 20
> 
>  
> 
> 4) (IN) IPv4    -> IPv6            Dout = -30, Din = 20
> 
> L4 = 40                   -> L6 = 60          D'out = 0, D'in = 20
> 
> SNin = 540      -> SN'in = SNin + Din = 560
> 
> ANin = 160     -> AN'in = ANin - Dout = 190
> 
> Result: Dout += D'out = -30, Din += D'in = 40
> 
>  
> 
> 5) (IN) IPv4    -> IPv6            Dout = -30, Din = 40
> 
> L4 = 40                   -> L6 = 60          D'out = 0, D'in = 20
> 
> SNin = 580      -> SN'in = SNin + Din = 620
> 
> ANin = 160     -> AN'in = ANin - Dout = 190
> 
> Result: Dout += D'out = -30, Din += D'in = 60
> 
>  
> 
> 6) (OUT) IPv4            <-        IPv6     Dout = -30, Din = 60
> 
> L4 = 30                   <-            L6 = 40           D'out = -10, D'in = 0
> 
> SN'out = SNout + Dout = 160            <-        SNout = 190
> 
> AN'out = ANout - Din = 560  <-        ANout = 620
> 
> Result: Dout += D'out = -40, Din += D'in = 40
> 
> As you can see, packets 4 and 5 comes from the same direction, both modify Din and 
>when packet 6 arrives in the other direction, it takes the last known Din to 
>calculate AN'out. As the packet 6 is the answer for packet 4, it should have 
>AN'out=580 and not 560.
> 
> What do you think of this?
> 
> Juan Luis
> -- 
> Get your free email from www.linuxmail.org 
> 
> 
> Powered by Outblaze
> ---------------------------------------------------------------------
> The IPv6 Users Mailing List
> Unsubscribe by sending "unsubscribe users" to [EMAIL PROTECTED]
> 

-- 
Get your free email from www.linuxmail.org 


Powered by Outblaze
---------------------------------------------------------------------
The IPv6 Users Mailing List
Unsubscribe by sending "unsubscribe users" to [EMAIL PROTECTED]

Reply via email to