> Marc Vanbrabant wrote:
> I would say the follow (though consider me newbie):
> 193.109.122.62 = ::ffff:193.109.122.62/96;
No. First, you did not mention a subnet mask for the IPv4 address, but the only thing
that would match /96 would be /0 for v4, no go. What you should have written is:
193.109.122.62/32 = ::ffff:193.109.122.62/128
�
> If you want a subnet like:
> 193.109.122.62/29
This has never been a subnet. The network address for this IP and subnet mask is
193.109.122.56.
�
> that would be
> ::ffff:193.109.122.62/125;
Wrong. That would be ::ffff:193.109.122.56/125
>�/125 from /96 + /29
This part is correct.
Michel.
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