Re: Returning results of Wicket search component

[Erik de Hair]

For now I've got it working. Is there a better way of executing the 
action and returning the correct page?

final ObjectAdapter serviceAdapter = 
getServiceAdapter(SearchService.class.getName());
        final ObjectAction action = 
serviceAdapter.getSpecification().getObjectAction("find");

        ActionModel actionModel = ActionModel.create(serviceAdapter, 
action);

        List<ActionParameterMemento> parametersList = 
actionModel.primeArgumentModels();

        AdapterManager am = (AdapterManager)getPersistenceSession();
        for (ActionParameterMemento actionParameterMemento : 
parametersList)
        {
            ScalarModel arg = 
actionModel.getArgumentModel(actionParameterMemento);
            switch (actionParameterMemento.getNumber())
            {
                case 0:
                    arg.setObject(am.adapterFor(this.query));
                    break;
                case 1:
                    if(this.preference != null)
                    {
arg.setObject(am.adapterFor(SearchService.Type.valueOf(this.preference)));
                    }
                    break;
                case 2:
                    arg.setObject(am.adapterFor(boost));
                    break;
                default:
                    break;
            }
        }

        ObjectAdapter resultAdapter = action.execute(serviceAdapter, 
actionModel.getArgumentsAsArray(), InteractionInitiatedBy.USER);

        ActionResultResponse resultResponse = 
ActionResultResponseType.COLLECTION.interpretResult(actionModel, null, 
resultAdapter);
        resultResponse.getHandlingStrategy().handleResults(this, 
resultResponse);

On 12/21/2015 09:10 AM, Erik de Hair wrote:
Hi,

I'm trying to create a generic search component that should show up in 
the footer bar. Creating the component itself is not a problem but 
returning the results is. The component is calling a service like this:

final SearchService searchService = lookupService(SearchService.class);
SortedSet<SearchResult> results = searchService.find(this.query, null, 
1);

I was thinking about returning a StandaloneCollectionPage or ViewModel 
by using ActionResultResponseType but I can't figure out to create the 
model right. So how to set the response page with the right parameters?

Thanks,
Erik