Hi Bertrand, Thanks for your answer. In fact this is not what I need. I know about the getNodes() method, but I was thinking to get a node with a path, not by making a "hack" with java code. Something like /foo/bar/jcr:child(5) for example, if jcr:chile(x) was a path util retrieving the xth child of the parent node (here the bar node).
Frédéric Esnault -----Message d'origine----- De : [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] De la part de Bertrand Delacretaz Envoyé : mardi 26 juin 2007 11:18 À : [email protected] Objet : Re: getNode without the name On 6/26/07, Frédéric Esnault <[EMAIL PROTECTED]> wrote: > ...For example, under the lgw:contracts node, I have plenty of nodes named > with their > uuid. I want, from the lgw:contracts node, to get the node with index 5. Not sure what you mean by index, but Node.getNodes() returns a NodeIterator, and with NodeIterator.skip(int n) you can move to a specific child. Isn't that what you need? -Bertrand
