Hi,
On 8/8/07, Amir Mistric <[EMAIL PROTECTED]> wrote:
> - What is the *best* way to find out if a child node is the last child of its
> parent (based on certain node type)?
> - Is there an API that already does this or would I have to create my
> own method.
> - If I have to create my own method, what would you recommend?
> Do an Xpath query using last() or get a count of children and compare
> last child node with passed in one?
JCR doesn't have methods like Node.getNext() or Node.getPrevious()
that would allow you to do sideways traversal.
I guess the best way to achieve your goal would be:
Node node = ...
NodeIterator iterator = node.getParent().getNodes();
while (iterator.hasNext()) {
if (node.isSame(iterator.nextNode())) {
if (iterator.hasNext()) {
return /* this is not the last sibling */;
} else {
return /* this is the last sibling */;
}
}
}
This approach is obviously not too efficient, but can be used to
implement your use case as well as the "next"/"previous" links
discussed in another post a while ago.
Perhaps we should ask for JSR 283 to consider adding support for
sibling access methods?
BR,
Jukka Zitting
