Re: disjointWith classes

[Dave Reynolds]

You don't need to load your ontology twice. An OntModel is just a 
wrapper round an underlying model so you can construct both a 
with-inference and a without-inference OntModel over the same Model.

Dave
On 25/01/13 03:35, Emanuel Santos wrote:
Hi Tayfun,

Thank you so much!

That way only works if I choose a model without any class-hierarchy
inference. Of course.

When I'm working with a model with class-hierarchy inference (e.g.
OWL_MEM_TRANS_INF
ou a reasoner) can I still get the direct Disjointwith classes ?? I tried
it getting them using the baseModel but the "as(OntClass.class)" part
doesn't work. If there isn't any other way...I'm doomed to load 2x my
ontology... it is not good :) Any ideas ?

Thanks!

best,

Emanuel




On 24 January 2013 22:32, Tayfun Gökmen Halaç
<tayfunhalac.apa...@gmail.com>wrote:

Hi Emanuel,

Not with a direct method. You can obtain those sets with a modified version
of previous solution.

// create the ontology...
OntModel model = ModelFactory.createOntologyModel();
OntClass classA = model.createClass("http://bla.bla/A";);
OntClass classB = model.createClass("http://bla.bla/B";);
OntClass classC = model.createClass("http://bla.bla/C";);
OntClass classD = model.createClass("http://bla.bla/D";);

classA.addDisjointWith(classB);
classA.addDisjointWith(classC);

classC.addDisjointWith(classD);

// list disjoint sets...
ResIterator classesHasDisjoint = model
.listResourcesWithProperty(OWL.disjointWith);
while (classesHasDisjoint.hasNext()) {
OntClass cls = classesHasDisjoint.next().as(OntClass.class);
List<OntClass> disjointList = cls.listDisjointWith().toList();
disjointList.add(0, cls);
System.out.println(disjointList);
}

Console output:
[http://bla.bla/A, http://bla.bla/C, http://bla.bla/B]
[http://bla.bla/C, http://bla.bla/D]

Best,
Tayfun


2013/1/24 Emanuel Santos <edpsan...@gmail.com>

Hi,

Thanks for the reply!

Maybe I was not clear.

For instance, given these classes:

     <owl:Class rdf:about="http://bla#A!>
         <owl:disjointWith rdf:resource="http:/bla#B"/>
         <owl:disjointWith rdf:resource="http:/bla#C"/>
     </owl:Class>

     <owl:Class rdf:about="http://bla#C";>
         <owl:disjointWith rdf:resource="http:/bla#D"/>
     </owl:Class>

I want to obtain these sets : {A,B,C} and {C,D}.
Only the direct classes.

Thanks!






On 24 January 2013 14:03, Fabio Aiub Sperotto <fabio.a...@gmail.com>
wrote:

Hi Emanuel,

I don't know if I have a good solution for you (I'm not the best
programmer), but recently I made this: Search for all classes of
ontology.
For each class X, return the set of classes that is disjoint with X:

         model.read(new InputStreamReader(in), ""); //read the ontology

         Iterator classes = model.listClasses(); //list all classes in
ontology
         while (classes.hasNext()){
             OntClass ontologyClass = (OntClass) classes.next(); //get
one
class

             //get list of disjoint classes from ontologyClass
             Iterator disjointClasses =
ontologyClass.listDisjointWith();

             while(disjointClasses.hasNext()){
             System.out.print("Class "+ontologyClass.getLocalName()+" is
disjoint with: ");
             System.out.println(disjointClasses.next());
             }
             System.out.println("");

         }

This will help? My some mistake?


2013/1/24 Emanuel Santos <edpsan...@gmail.com>

Hi,

I just started using Jena.
Any easyway to get all set of classes "disjointWith" ?

Thanks




--
Fabio Aiub Sperotto
Mestrando em Modelagem Computacional
about.me/fabiosperotto
www.twitter.com/fabio_gk