On Thu, Oct 17, 2013 at 3:07 PM, Joshua TAYLOR <[email protected]> wrote:
> On Thu, Oct 17, 2013 at 1:15 PM, Ralph Perniciaro
> <[email protected]> wrote:
>> What is the best way to export an individual from a Model to RDF. I don't
>> want to export the entire Model to RDF, just a specific individual or
>> resource. Also, I would like to include any resources that the individual
>> is related to, along with it's properties, if it is defined in that model.
>> Another way of looking at this would be replicating a resource and its
>> associated resources to another model.
>
> It's probably creating a new model, iterating through the statements
> that have that resource as a subject, and adding those statements to
> the new model. You could do this with Model.listStatements(...) [1],
> which returns a StmtIterator, and model.add(StmtIterator) [2]. I
> would look more or less like:
>
> newModel.add( oldModel.listStatements( theResource, null, null ));
Rereading your original email, it seems like you might have wanted
another level deep, in which case you could do it with listStatements,
but it's probably easier to just run a SPARQL construct query that
will return a model to you. It'd look like
construct { <theResource> ?p ?o . ?o ?p2 ?o2 . }
--
Joshua Taylor, http://www.cs.rpi.edu/~tayloj/
