Hi guys:
I would like to save my SPARQL result coming from ResultSet into new rdf.
(new rdf resources) cause I want to do more work on this subgraph and it
has to be in the original rdf format.
I tried outputAsRDF function and it worked however the result I got the
following:
<rdf:Description rdf:nodeID="A5">
<rs:value rdf:resource="
https://csel.cs.colorado.edu/~noor/Drug_Disease_ontology/DDID.owl#genotypePhenotype
"/>
<rs:variable>omimt</rs:variable>
</rdf:Description>
<rdf:Description rdf:nodeID="A6">
<rs:value rdf:resource="
https://csel.cs.colorado.edu/~noor/Drug_Disease_ontology/DDID.rdf#C0007589
"/>
<rs:variable>w</rs:variable>
</rdf:Description>
<rdf:Description rdf:nodeID="A7">
<rs:binding rdf:nodeID="A8"/>
<rs:binding rdf:nodeID="A9"/>
<rs:binding rdf:nodeID="A10"/>
<rs:binding rdf:nodeID="A11"/>
<rs:binding rdf:nodeID="A12"/>
<rs:binding rdf:nodeID="A13"/>
<rs:binding rdf:nodeID="A14"/>
<rs:binding rdf:nodeID="A15"/>
<rs:binding rdf:nodeID="A16"/>
<rs:binding rdf:nodeID="A17"/>
<rs:binding rdf:nodeID="A18"/>
<rs:binding rdf:nodeID="A19"/>
<rs:binding rdf:nodeID="A20"/>
<rs:binding rdf:nodeID="A21"/>
<rs:binding rdf:nodeID="A22"/>
<rs:binding rdf:nodeID="A23"/>
<rs:binding rdf:nodeID="A24"/>
<rs:binding rdf:nodeID="A25"/>
<rs:binding rdf:nodeID="A26"/>
<rs:binding rdf:nodeID="A27"/>
</rdf:Description>
how I can remove this nodes things and make it something like:
<rdf:Description rdf:about="
https://csel.cs.colorado.edu/~noor/Drug_Disease_ontology/DDID.rdf#C3229174";>
<j.0:label>Cytra-K Oral Product</j.0:label>
<rdf:type rdf:resource="
https://csel.cs.colorado.edu/~noor/Drug_Disease_ontology/DDID.owl#chemical
"/>
</rdf:Description>
please help me out
--
Adeeb Noor
Ph.D. Candidate
Dept of Computer Science
University of Colorado at Boulder
Cell: 571-484-3303
Email: [email protected]
