it is possible to use SQWRL from jena api instead of using SPARQL?
2014-04-23 13:40 GMT+02:00 ameni ameni <[email protected]>: > Sorry > > > 2014-04-23 9:28 GMT+02:00 Dave Reynolds <[email protected]>: > > On 23/04/14 00:22, ameni ameni wrote: >> >>> How can i get accesed to the conclusion of SWRL rules from Jena API ? >>> >>> >> Asking the same question multiple different ways, especially when it has >> already been answered, is not good practice and doesn't encourage people to >> try to help you. Please don't. >> >> To summarize and explain the responses you've had so far: >> >> 1. Pellet includes some support for SWRL but is not part of the Jena >> project. For all help on how to configure it and debug it you are better >> off asking on the pellet support list. >> >> 2. From Jena's point of view the reasoner simply makes additional >> inferred triples available in the model. You can then query for these >> triples using the API or SPARQL in the normal way. >> >> 3. Your specific example was of the form: >> blah -> adult(?x) >> >> In terms of the RDF model this will, if it fires, create inferred triples >> of the form: >> >> x rdf:type ex:Adult >> >> So a query like: >> >> SELECT ?x WHERE { ?x a ex:Adult } >> >> is appropriate. >> >> We can't tell you what ex: is, that's in your data. If you can't figure >> it out then you could try to run a query like: >> >> SELECT DISTINCT ?type WHERE { [] a ?type } >> >> over your inferred model and see what ?types are present. >> >> Or if your data is not too big: >> >> SELECT * WHERE { ?x a ?type } >> >> to find the type of everything. >> >> If there is nothing related to Adult in there then perhaps your rule >> hasn't fired. >> >> Dave >> >> >
