I'm using whatever default setting there is.
How do I check this?

Thanks,
Hubert



On Thu, May 22, 2014 at 9:50 AM, Andy Seaborne <[email protected]> wrote:

> Do you have TDB defaultUnionGraph turned on?
>
> On 22 May 2014 16:51, Hubert Le Van Gong <[email protected]> wrote:
> > Cool, it worked fine.
> >
> > Just curious, I noticed that the named graphs end up embedded in the
> > required default (nameless) graph (see below).
> > Any particular reason to do this and not have the default graph empty,
> > followed by the named graphs?
> >
> > Cheers,
> > Hubert
> >
> > {
> >   "@graph" :
> >   [
> > {
> >   "@graph" :
> >   [...],
> > "@id" : "http://example.org/graph1";
> > },
> > {
> > "@graph" :
> > [...],
> > "@id" : "http://example.org/graph2";
> > },
> >   ]
> > }
> >
> >
> > On Thu, May 22, 2014 at 4:16 AM, Andy Seaborne <[email protected]> wrote:
> >
> >> On 22/05/14 03:03, Hubert Le Van Gong wrote:
> >>
> >>> Greetings,
> >>>
> >>> I have a set of N-Quad statements that relate to different graphs. How
> do
> >>> I
> >>> go about exporting all those statements into a single JSON-LD object?
> >>>
> >>> For instance, I would expect that something like:
> >>> <http://one.example/subject3> <http://one.example/predicate3> <
> >>> http://one.example/object3> <http://example.org/graph3> .
> >>> _:subject1 <http://an.example/predicate1> "object1" <
> >>> http://example.org/graph1> .
> >>> _:subject2 <http://an.example/predicate2> "object2" <
> >>> http://example.org/graph2> .
> >>>
> >>> would end up as the following JSON-LD (disclaimer: I'm not 100% sure
> this
> >>> is correct, JSON-LD wise):
> >>>
> >>> [
> >>> {
> >>> "@context": {
> >>> "predicate3": "http://one.example/predicate3";
> >>> },
> >>> "@id": "http://example.org/graph3";,
> >>> "@graph":
> >>> [
> >>> {
> >>> "@id": "http://one.example/subject3";,
> >>> "predicate3": "http://one.example/object3";
> >>> }
> >>> ]
> >>> },
> >>> {
> >>> "@context": {
> >>> "predicate1": "http://an.example/predicate1";
> >>> },
> >>> "@id": "http://example.org/graph1";,
> >>> "@graph":
> >>> [
> >>> {
> >>> "@id": "_:b0",
> >>> "predicate1": "object1"
> >>> }
> >>> ]
> >>> },
> >>> {
> >>> "@context": {
> >>> "predicate2": "http://an.example/predicate2";
> >>> },
> >>> "@id": "http://example.org/graph2";,
> >>> "@graph":
> >>> [
> >>> {
> >>> "@id": "_:b0",
> >>> "predicate2": "object2"
> >>> }
> >>> ]
> >>> }
> >>> ]
> >>>
> >>>
> >>> So far, the approach I took was to load the n-quads using:
> >>> RDFDataMgr.read(dataset, in, RDFLanguages.NQUADS);
> >>>
> >>
> >>
> >>
> >>> and then iterate through the graph names, to get each model with:
> >>> Model model = dataset.getNamedModel(name);
> >>>
> >>> Something like model.write(out, RDFLanguages.strLangJSONLD); works
> well to
> >>> convert the data to JSON-LD, however it does not add any graph info
> >>> (@graph).
> >>> While I could probably stitch those parts together, I was hoping for a
> >>> cleaner way to do this.
> >>>
> >>
> >> If you write the whole dataset:
> >>
> >> RDFDataMgr.write(System.out, dataset, Lang.JSONLD) ;
> >>
> >> all the graphs will come out, named.
> >>
> >> If you want to print one graph, with it's name, create a separate
> dataset,
> >> put just that graph in it, as a named graph, and print that.
> >>
> >> Models don't have names - it's the container (dataset) that gives it
> it's
> >> name.  It can have several names (be included several times, or in
> several
> >> places).
> >>
> >>         Andy
> >>
> >>
> >>
> >>> In particular, I tried to create a new model by uniting 2 models at a
> time
> >>> but it did not quite work (although I do see @graph added)...
> >>>
> >>> Can anyone shed some light on the best approach for this?
> >>>
> >>> Cheers,
> >>> Hubert
> >>>
> >>> PS: my apologies if it's already been discussed before but I did not
> find
> >>> anything on this particular topic in the list archive.
> >>>
> >>>
> >>
>

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