On 06/02/15 09:54, Stian Soiland-Reyes wrote:
Or use CONSTRUCT WHERE {} shorthand:
http://www.w3.org/TR/sparql11-query/#constructWhere
I must admit I didn't check if this works in Jena, but given that Andy
cowrote the spec... :-)
Yes, it works.
It's syntactic sugar the parser sorts out. It's not even in the
abstract syntax tree.
arq.qparse 'CONSTRUCT WHERE {?s ?p ?o}'
==>
CONSTRUCT
{ ?s ?p ?o .}
WHERE
{ ?s ?p ?o}
Andy
On 6 Feb 2015 09:39, "Andy Seaborne" <[email protected]> wrote:
On 06/02/15 02:32, Kamalraj Jairam wrote:
Hello All,
How do i convert a sparql resultset to a model ?
Is it possible without transforming the spraql select query to a
construct query?
Thanks
Kamalraj
What are you trying to do?
You can convert a ResultSet to a model with ResultSetFormatter.toModel.
It's really left-over code from the days when SPARQL testing looked like it
would be model based.
It is encoding the result set, and it's not related to the vocabulary of
the model queried. Try it out to see the vocabulary used.
Andy
