On 22/12/15 19:09, A. Soroka wrote:
Were you using that with an inferring model? Because then you are going to
materialize a bunch of fresh rdf:type triples, which are going to turn up as
the other (super) classes.
Chris : "directly implemented" -- do you mean direct subclasses?
http://jena.apache.org/documentation/inference/index.html#directRelations
C is not a direct subclass of A.
There is some secret predicate when querying an inference model (not
sure what it is. Dave?) that will trigger direct subclass calculation.
If you want SPARQL and use the right predicate it should work.
Otherwise on the base data, not the inference model:
A quick hack in SPARQL for a non-inference model for direct subClassOf:
# ?x is a direct subclass of ?C if
# there is not a another, longer route to it.
PREFIX : <http://example/>
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
SELECT * {
?x rdfs:subClassOf ?C .
FILTER NOT EXISTS { ?x rdfs:subClassOf/rdfs:subClassOf+ ?C }
}
--------------------------------------
@prefix : <http://example/> .
@prefix rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#> .
@prefix rdfs: <http://www.w3.org/2000/01/rdf-schema#> .
:B rdfs:subClassOf :A .
:C rdfs:subClassOf :A .
:C rdfs:subClassOf :B .
:D rdfs:subClassOf :B .
-----------
| x | C |
===========
| :C | :B |
| :D | :B |
| :B | :A |
-----------
---
A. Soroka
The University of Virginia Library
On Dec 22, 2015, at 1:58 PM, Chris Snyder <[email protected]> wrote:
Yeah, I tried that route but it still returns all the class in the inheritance
structure.
Thanks,
Chris
On Dec 22, 2015, at 11:52 AM, A. Soroka <[email protected]> wrote:
I am _no_ SPARQL guru, but I think you might be able to do this without
inference, with property paths:
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX owl: <http://www.w3.org/2002/07/owl#>
PREFIX modelica: <http://mind-tap.net/kbswt/modelica#>
SELECT ?instance ?label
WHERE {
?instance rdf:type ?type.
?type rdfs:subClassOf+ modelica:BinaryExpression .
?type rdfs:label ?label.
}
---
A. Soroka
The University of Virginia Library
On Dec 22, 2015, at 11:41 AM, Chris Snyder <[email protected]> wrote:
I’m using the Jena OWL reasoner with this ontology:
http://www.mind-tap.net/kbswt/simple_no_inheritance.ttl
I want to get the named individuals that are instances of a
modelica:BinaryExpression along with the rdfs:label of the class directly
implemented by the named individual.
I hope there is a SPARQL guru who can help identify what I need to do. If
adding a Jena rule to the reasoner would help I have no problem going that
route either.
In essence:
c subClassOf b
b subClassOf a
c rdfs:label “class c”
b rdfs:label “class b”
a rdfs:label “class a”
x typeOf c
x rdfs:label “instance x”
I need to run a query to get:
“instance x”, “class c”
but my SPARQL gives me:
“instance x”, “class c”
“instance x”, “class b”
“instance x”, “class a”
I’ve tried some filter expressions but they wind up filtering out all the
results. I was thinking there is some path modifier that might work but haven’t
been successful going down that route either.
My starter SPARQL:
PREFIX modelica: <http://mind-tap.net/kbswt/modelica#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX : <http://mind-tap.net/kbswt/simple_no_inheritance#>
select distinct * { ?s rdfs:subClassOf modelica:BinaryExpression ;
rdfs:label ?equationName .
?i a ?s.
}
ORDER BY ?i
Thanks in advance,
Chris
