I am sorry Lorenz for late reply. It gives me the now the integer number. I do not know even now how, but I made some random changes to the code and it shows me the result now.
Kind regards On Thu, Sep 29, 2016 at 12:33 AM, Lorenz B. < [email protected]> wrote: > Obviously not, otherwise you wouldn't get a parse exception?! You can't > have a filter outside of the query. See SPARQL specs and/or tutorials. > > And that's what we already told you in the other thread. > > You know, it's really strange that you do not answer our questions. So > again, how can you get the exception with the literals given that your > query does not compile and thus you can't get to the point where > literals would have been parsed to Java objects? > > > SELECT *" + > > " WHERE { ?x rdf:type ont:Team . ?x ont:team_goal > ?goal > > . ?x ont:team_wins ?wins} filter(?goal>10 && ?wins<?goal ) "; > > > > Is this syntax correct because it gives me error:* Encountered " "filter" > > "filter "" at line 1, column 265.* > > > -- > Lorenz Bühmann > AKSW group, University of Leipzig > Group: http://aksw.org - semantic web research center > >
