Take a look at ResultSetFactory: https://jena.apache.org/documentation/javadoc/arq/org/apache/jena/query/ResultSetFactory.html
On Mon, Mar 26, 2018 at 6:48 PM, Élie Roux <[email protected]> wrote: > Dear All, > > I'm trying to transform a String in the format of a SPARQL Select JSON > Result into a org.apache.jena.query.ResultSet, but it proves much more > difficult than I anticipated. What I'm trying to achieve is really > starting with a json string, I can't use a QueryExecution.execSelect(). > > I initially tried: > > ResultSet res = ResultSetMgr.read(myjsonstring, Lang.JSONLD); > > but the second argument is obviously wrong and there doesn't seem to be > a Lang for the SPARQL json result format. > > I then tried to understand how the ResultSet was constructed in > QueryExecution.execSelect, but I have to admit I got lost very quickly > as there are many classes I'm not familiar with (Plan for instance)... > > Is there something obvious (or non-obvious) that I missed? Is it > possible to achieve what I want? > > Thank you, > -- > Elie >
