On Mon, 2018-11-05 at 15:00 +0100, Dario Lesca wrote:
> When I concatenate 2 or more shell command with pipe (|), I get only
> the status of last one.
>
> For example: "some-cmd | logger -t "some-cmd messages:"; echo $?"
>
> If "some-cmd" fail with status !=0 I get always status of last one,
> in this case 0
>
> In my case if the first command fail, I must send a warning message
>
> A more simple example is: "false | true"
>
> I want get status 1, of first command (false), not 0 (true)
>
> I have also try "sh -e -c 'false || exit 2|true'; echo $?" but I get
> always 0
>
> How to I get first status and break the chains of pipes ?
Assuming that your shell is bash:
set -o pipefail
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