This may just be how Python works, but I wanted to check with you guys
first.
Say I have an assembly named MyLibrary that contains the following code:
namespace MyLibrary
{
public interface IMyInterface
{
string MyProperty{ get;}
}
public class MyClass : IMyInterface
{
string IMyInterface.MyProperty
{
get { return "MyInterface version of MyProperty"; }
}
public string MyProperty
{
get { return "MyClass version of MyProperty"; }
}
public static IMyInterface GetInterface(){ return new MyClass();}
public static MyClass GetClass() { return new MyClass(); }
}
}
-------------------------------------------------------------
A console application with the following code
MyLibrary.IMyInterface a = MyLibrary.MyClass.GetInterface();
Console.WriteLine("MyInterface call = " + a.MyProperty);
MyLibrary.MyClass b = MyLibrary.MyClass.GetClass();
Console.WriteLine("MyClass call = " + b.MyProperty);
Will produce the following output:
MyInterface call = MyInterface version of MyProperty
MyClass call = MyClass version of MyProperty
-------------------------------------------------------------
Now if I use IronPython and write a script that looks like the following
import clr
clr.AddReference("MyLibrary")
import MyLibrary
a = MyLibrary.MyClass.GetInterface()
print "MyInterface call = ", a.MyProperty
b = MyLibrary.MyClass.GetClass()
print "MyClass call = ", b.MyProperty
The output of this script is
MyInterface call = MyClass version of MyProperty
MyClass call = MyClass version of MyProperty
I've been testing IronPython on our CAD application and everything has been
working great except for this issue. It is actually a pretty big issue for
me because the way I wrapped our C++ SDK for .NET uses this feature quite a
bit. If this is the expected result in python, is there a way to force the
interface version of the property_get function to be called?
Thanks,
-Steve
Steve Baer
Robert McNeel & Associates
www.rhino3d.com
www.mcneel.com
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