Am 22.03.2010 14:13, schrieb Uriel Rozenbaum:
Hey, thanks for both replies from Daniel and Klaus.
Klaus, will this work on kamailio 1.5.3 the same way?
AFAIK: yes
Daniel, sorry I misstyped. The first flags should be ocfaei and the
second ones ocfaie.
What I meant with the question is:
I receive an invite from public IP; I call force_rtp_proxy("ocfaei");
Then I receive the reply (lets say 183 or 200) and I call
force_rtp_proxy("ocfaie");
Is this right?
No, read the description:
'i' corresponds to rtpproxy's first interface
'e' corresponds to rtpproxy's second interface.
so you should use: rtpproxy -l PRIVATE_IP/PUBLIC_IP
Then, the force_rtp_proxy calls should work.
Further: if the client in the public network is behind NAT you should
not use the 'a' flag.
regards
klaus
Thanks in advance,
Uriel
On Mon, Mar 22, 2010 at 6:20 AM, Klaus Darilion
<[email protected] <mailto:[email protected]>> wrote:
Recently I have rewritten the documentation about using the e/i
flag. See
http://sip-router.org/docbook/sip-router/branch/master/modules_k/nathelper/nathelper.html#id2907572
regards
klaus
Am 19.03.2010 22:12, schrieb Uriel Rozenbaum:
Hi guys,
I have some easy doubt about nathelper functions using RTPProxy.
I'm trying to bridge from an external IP to an internal IP.
The start-line for rtpproxy is: rtpproxy -l PUBLIC_IP/PRIVATE_IP -s
udp:127.0.0.1:7999 <http://127.0.0.1:7999>
<http://127.0.0.1:7999> -F
It starts OK and I see it when kamailio starts.
I'm going to use something like Daniel showed on some other mail:
if(dst_ip==private)
force_rtp_proxy("ocfaei");
else
force_rtp_proxy("ocfaei");
if i have the invite from a public IP to someone in private on the
request I'll run
force_rtp_proxy("ocfaei");
then the reply will be from private to public... should I run
"force_rtp_proxy("ocfaei");"? or should it be the same?
As allways, thanks for your help.
Kind regards,
Uriel
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