Hi Jeff,
the correct format is the first one:
$(var(xyz){param.value,peer}{s.unescape.user})
but you mentioned errors for it, so these are startup or runtime errors?
can you post them?
Regards,
Bogdan
Jeff Pyle wrote:
> Hello,
>
> What is the proper way to apply multiple string transformations at the same
> time?
>
> For example, let's say I want to extract the {param.value,peer} from
> $var(xyz) and then do a {s.unescape.user} on it? All the combinations I've
> tried have errored out:
>
> $(var(xyz){param.value,peer}{s.unescape.user})
> $(var(xyz){param.value,peer}){s.unescape.user}
> ... and more failures.
>
>
> Thanks,
> Jeff
>
>
>
>
>
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