I found what was going on more in details, when the second call comes in the RTP port is set as the correct one from the first call, however, I issue another use_media_proxy() and a new port is set, I guess I could ignore the use media proxy this time by validating if the IP of the media proxy is already in SDP "m=audio x.x.x.x", I will try this Opensip_A --invite--> B2B_UA m=audio 52542 RTP/AVP 18 8 0 B2B_UA --invite--> Opensip_A m=audio 52542 RTP/AVP 18 8 0 (use media proxy) Opensip_A --invite--> UA_B m=audio 50506 RTP/AVP 18 8 0
________________________________ From: [email protected] on behalf of Julien Chavanton Sent: Tue 19/01/2010 6:43 PM To: [email protected] Subject: [OpenSIPS-Users] media proxy - B2BUA(signaling only) Hi, I have this senario : UA_A --> Opensip_A --> SIP_B2BUA(signaling only) --> Opensip_A --> UA_B this result is 2 calls(different callid) on Opensip_A however UA_A and UA_B are connecting the the MediaProxy on 2 differents calls and the audio is not bridged between them. It there a way the make the media proxy aware about the fact that the 2 calls should be bridged ?
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