Hi all, I have one particular application as follows. Suppose client A and client B had a video call recorded at the rtpproxy a few days ago. Now client B would like to watch the recorded session from client A to itself. The document of rtpproxy says that it can play a pre-recorded file to a client and OpenSIPS provides rtpproxy_stream2uac in the RTPPROXY module. I call start_record() to make rtpproxy record the video call (which consists of 8 files (2 (caller/callee) x 2 (audio/video) x 2 (rtp/rtcp)). However, I do not realize how to use rtpproxy_stream2uac() to make client B can watch what client A sent to him/her a few days ago. I find very few threads on the usage of rtpproxy_stream2uac in this forum. My questions are specifically listed below.
1. The rtpproxy play the file in what format to the client? Do I need to merge .rtp .rtcp files into one file in the format like mp4? Since rtpproxy_stream2uac only provides a file name, I don't know how client B can receive audio and video streams. 2. Client B wants to watch the recorded video call and thus no so-called callee in such a case. From rtpproxy_stream2uac(), it seems that one caller and one callee are required? Anyone has similar experience on this issue? Any comment is appreciated. PS. The versions of OpenSIPS and rtpproxy I used are branch 9585 and 1.2.1, respectively. Best regards, Chen-Che -- View this message in context: http://opensips-open-sip-server.1449251.n2.nabble.com/About-rtpproxy-stream2uac-tp7587696.html Sent from the OpenSIPS - Users mailing list archive at Nabble.com. _______________________________________________ Users mailing list [email protected] http://lists.opensips.org/cgi-bin/mailman/listinfo/users
