Dear all,

?I have some trouble in understanding why equivalent (if I am not
wrong) representation of the crystal structure leads to different
symmetry (as shown in the output from pw.x). All input/output
files are attached.

I work with rhombohedral unit cell, alat = 5.46 Ang, gamma =60.36.
First, I let PWscf to build lattice vectors using the following
settings:

? ? ? ? ? ? ? ? ? ? ? ibrav = 5 ,
? ? ? ? ? ? ? ? ? celldm(1) = 10.317903898
? ? ? ? ? ? ? ? ? celldm(4) = 0.494548768
......

The code generates lattice vectors:

? ? celldm(1)= ?10.317904 ?celldm(2)= ? 0.000000 ?celldm(3)= ? 0.000000
? ? celldm(4)= ? 0.494549 ?celldm(5)= ? 0.000000 ?celldm(6)= ? 0.000000

? ? crystal axes: (cart. coord. in units of a_0)
? ? ? ? ? ? ? a(1) = ( ?0.502718 -0.290245 ?0.814268 )
? ? ? ? ? ? ? a(2) = ( ?0.000000 ?0.580489 ?0.814268 )
? ? ? ? ? ? ? a(3) = ( -0.502718 -0.290245 ?0.814268 )

? ? reciprocal axes: (cart. coord. in units 2 pi/a_0)
? ? ? ? ? ? ? b(1) = ( ?0.994593 -0.574229 ?0.409366 )
? ? ? ? ? ? ? b(2) = ( ?0.000000 ?1.148457 ?0.409366 )
? ? ? ? ? ? ? b(3) = ( -0.994593 -0.574229 ?0.409366 )

and shows that

? ?6 Sym.Ops. (no inversion)

? ? point group C_3v (3m)
? ? there are ?3 classes
? ? the character table:

? ? ? E ? ? 2C3 ? 3s_v
A_1 ? ?1.00 ?1.00 ?1.00
A_2 ? ?1.00 ?1.00 -1.00
E ? ? ?2.00 -1.00 ?0.00

? ? the symmetry operations in each class:
? ? E ? ? ? ?1
? ? 2C3 ? ? ?2 ? ?3
? ? 3s_v ? ? 4 ? ?5 ? ?6


However, I prefer to work with lattice vectors directly and then
changed my settings

from :

? ? ? ? ? ? ? ? ? ? ? ibrav = 5 ,
? ? ? ? ? ? ? ? ? celldm(1) = 10.317903898
? ? ? ? ? ? ? ? ? celldm(4) = 0.494548768


to:

? ? ? ? ? ? ? ? ? ? ? ibrav = 0 ,
? ? ? ? ? ? ? ? ? celldm(1) = 10.317903898
? ? ? ? ? ? ? ? ? ?.......

? ?CELL_PARAMETERS
? ? ? ? ? ? ? ?0.502718 -0.290245 ?0.814268
? ? ? ? ? ? ? ?0.000000 ?0.580489 ?0.814268
? ? ? ? ? ? ? -0.502718 -0.290245 ?0.814268

CELL_PARAMETERS were taken from the output when I use first settings
(see above, crystal axes: (cart. coord. in units of a_0)). ?However,
now the code shows different symmetry:

2 Sym.Ops. (no inversion)
? ? point group C_s (m)
? ? there are ?2 classes
? ? the character table:

? ? ? E ? ? s
A' ? ? 1.00 ?1.00
A'' ? ?1.00 -1.00

Frankly speaking, I cannot identify what I did wrong. I think, there
is a simple explanation, but I failed to find one. Any ideas?

Best wishes,


-- 
=====================================
Jess Kondor

NSTI
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