Dear Hasan,

> Actually, being  R (or IR) active of acoustic modes arouses suspicion about 
> calculation.

I do not know how the IR/Raman character of lattice vibrations is assigned in 
QE (Andrea Dal Corso may want to comment on this). All I can say is that 
symmetry analysis alone can only say if a mode *may* be Raman. IR active or 
not, *NOT* if it actually is. (i.e. it can only say which modes are inactive, 
not which ones are active). The resulting intensity may be exceedingly small 
(or even rigorously vanishing) for dynamical reasons that have nothing to do 
with symmetry. For instance, zone-center acoustic modes are inactive because of 
translational symmetry, which can hardly be detected by point-symmetry 
arguments. This is the case even for finite systems. Take any polar molecule 
(H2O, CO, ...) as an example. A rigid translation of the molecule (the 3 
independent such modes) has zero frequency and is IR and Raman inactive. I do 
not believe that such inactivity can be predicted by any rotational symmetry 
arguments ...

In any event, I think that if the code is incorrect, it should be easy to 
demonstrate. Just take the table of characters of the symmetry group of the 
system you are interested in, and assign the IR/Raman activity of each mode by 
yourself. It should not be difficult to do, and it is very instructive to do 
once in one's life, if you have never done it. If it turns out that the 
activities reported by QE are incorrect (either because the symmetry group is 
incorrectly assigned, or because the activity for a given group are incorrectly 
predicted), please revert to us with a detailed report.

Enjoy!
Stefano B

---
Stefano Baroni - SISSA  &  DEMOCRITOS National Simulation Center - Trieste
http://stefano.baroni.me [+39] 040 3787 406 (tel) -528 (fax) / stefanobaroni 
(skype)

La morale est une logique de l'action comme la logique est une morale de la 
pens?e - Jean Piaget

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