Stefano de Gironcoli wrote:
 > Stefano de Gironcoli wrote:
 >> ... Usually one takes a larger range (let's say 5-10
 >> %) which reduces the signal/noise ratio.
 >>
 > actually it increases the ratio... which is what one wants.

On the other hand, I think that if one uses a range that is too large then the 
bulk 
modulus comes out worse from the fit because the fitting model is not as good 
as near the 
minimum (you need more fitting parameters to describe properly the curve on a 
larger range).
Anyway, in my tests on a simple metal (bulk gold), the bulk modulus is not very 
sensitive 
to the fitting range. The "goodness" of the fit (chisq) seems to decrease with 
the range 
span (at fixed number of points), but the program does not give an estimate of 
the error 
on the fitting parameters.
I think that a good estimate of the bulk modulus can be obtained also with a 
small range 
(if your data is not too noisy and well centered around the minimum), but other 
paraters 
need a larger range. From the data below you can see that k0 (the bulk modulus) 
is very 
stable from a range span of 1% up to 5%, but in order to estimate dk0 you need 
at least 2%.
Maybe in other system this behaviour changes.

HTH,

Gabriele


==> Au.ev.1perc <==
# equation of state: murnaghan.        chisq = 0.7465D-12
# a0 =  7.67 a.u., k0 = 1923 kbar, dk0 =  1.76 d2k0 =  0.000 emin =  -66.84630
# a0 =  4.058 A,   V0 =112.706 (a.u.)^3,  V0 = 16.701 A^3

==> Au.ev.2perc <==
# equation of state: murnaghan.        chisq = 0.1161D-11
# a0 =  7.67 a.u., k0 = 1927 kbar, dk0 =  5.32 d2k0 =  0.000 emin =  -66.84630
# a0 =  4.057 A,   V0 =112.696 (a.u.)^3,  V0 = 16.700 A^3

==> Au.ev.3perc <==
# equation of state: murnaghan.        chisq = 0.1454D-11
# a0 =  7.67 a.u., k0 = 1925 kbar, dk0 =  5.51 d2k0 =  0.000 emin =  -66.84630
# a0 =  4.057 A,   V0 =112.693 (a.u.)^3,  V0 = 16.699 A^3

==> Au.ev.4perc <==
# equation of state: murnaghan.        chisq = 0.1438D-11
# a0 =  7.67 a.u., k0 = 1926 kbar, dk0 =  5.57 d2k0 =  0.000 emin =  -66.84630
# a0 =  4.057 A,   V0 =112.692 (a.u.)^3,  V0 = 16.699 A^3

==> Au.ev.5perc <==
# equation of state: murnaghan.        chisq = 0.1006D-10
# a0 =  7.67 a.u., k0 = 1922 kbar, dk0 =  5.61 d2k0 =  0.000 emin =  -66.84630
# a0 =  4.057 A,   V0 =112.692 (a.u.)^3,  V0 = 16.699 A^3

==> Au.ev.6perc <==
# equation of state: murnaghan.        chisq = 0.3205D-10
# a0 =  7.67 a.u., k0 = 1916 kbar, dk0 =  5.68 d2k0 =  0.000 emin =  -66.84630
# a0 =  4.057 A,   V0 =112.688 (a.u.)^3,  V0 = 16.699 A^3

==> Au.ev.7perc <==
# equation of state: murnaghan.        chisq = 0.1013D-09
# a0 =  7.67 a.u., k0 = 1909 kbar, dk0 =  5.70 d2k0 =  0.000 emin =  -66.84629
# a0 =  4.057 A,   V0 =112.689 (a.u.)^3,  V0 = 16.699 A^3

==> Au.ev.8perc <==
# equation of state: murnaghan.        chisq = 0.2887D-09
# a0 =  7.67 a.u., k0 = 1903 kbar, dk0 =  5.71 d2k0 =  0.000 emin =  -66.84629
# a0 =  4.057 A,   V0 =112.691 (a.u.)^3,  V0 = 16.699 A^3

==> Au.ev.9perc <==
# equation of state: murnaghan.        chisq = 0.7385D-09
# a0 =  7.67 a.u., k0 = 1894 kbar, dk0 =  5.70 d2k0 =  0.000 emin =  -66.84627
# a0 =  4.058 A,   V0 =112.697 (a.u.)^3,  V0 = 16.700 A^3





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| Gabriele Sclauzero, PhD Student                  |
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