Dear Nicola
> you need to consider what "more k-points" means - if you do > delta scf on a Bloch state you have a zero correction, as Stefano > pointed out. You can do it on a Wannier function (a sum of Bloch states > for all k-points), but then you do not have delta scf, and it's not > very different from having it on, say, an atomic orbital. > > I got your points. Thanks, Jie -------------- next part -------------- An HTML attachment was scrubbed... URL: http://www.democritos.it/pipermail/pw_forum/attachments/20101106/5a0c6706/attachment.htm
