Dear PWSCF users, I have a question regarding the order in which PDOS is written in fully relativistic case. As per documentation, it is
E LDOS(E) PDOS_1(E) ... PDOS_2j+1(E) Does PDOS_1(E) corresponds to -mj and '2j+1' to +mj. e.g. in case of P orbital, the order would corresponds to mj='-3/2,-1/2,1/2,3/2' for 4 columns printed or something else??? I would appreciate a clarification Saqib Javaid University of strasbourg. ---------------------------------------------------------------- This message was sent using IMP, the Internet Messaging Program.
