Dear Stefano Thanks for your good answer.I am an experimentalist and I learn good new things from your answer. My mistake was that I didnt know in calculation of pressure,we neglect electronic degrres of freedom(I will be thankfull to you,if you introduce a reference about this subject). I have another question :Is these terms are right? E=-PV+uN+TS => dE=-PdV-VdP+udN+Ndu+Tds+SdT and we know from first law of thermodynamics that dE=-PdV+udN+Tds and we conclude that -VdP+Ndu+SdT=0 and in zero temrature and fixed number of atoms we have dE=-PdV and P=-dE/dV
Thanks Meysam pazoki SUT -------------- next part -------------- An HTML attachment was scrubbed... URL: http://www.democritos.it/pipermail/pw_forum/attachments/20101015/acd26890/attachment.htm
