Hi, As far as I know,
psi(r) = \sum_k c(n,k)*exp(-i r*k) \sum_n c*(n,k)*c(n,k) = 1 It seemed to me that the psi^2 in post processing is different from what I wrote for the second equation. Hope that helps Best regards, Hongze On 12/06/2013, at 2:00 AM, pari shok <parishok at gmail.com> wrote: > Dear All, > Hi. > I was wondering whether the wavefunction squares calculated by > post-processing are normalized. > Thanks for any kinds of help. > P Shok > _______________________________________________ > Pw_forum mailing list > Pw_forum at pwscf.org > http://pwscf.org/mailman/listinfo/pw_forum -------------- next part -------------- An HTML attachment was scrubbed... URL: http://pwscf.org/pipermail/pw_forum/attachments/20130612/eb8cfd59/attachment.html
